Air conditioning power and floor space

The power of a domestic air conditioner is one of its most important characteristics. The size of the room that can cool the equipment depends on the power.

Air conditioning power and room area are closely interconnected. If the power is small, owners may not notice this until the hot summer days, when the device simply does not cool the air to the desired performance. At the same time, it will function as intensively as possible, putting the compressor at risk. The air conditioner installed in the fall can cope with its function in the off-season.

Do not go to the other extreme - to get too powerful air conditioning for the apartment. In a small room, residents will constantly be under a stream of icy air, which is harmful to health.

On the other hand, a powerful air conditioner on a smaller area will start more often, wearing out faster. Yes, and pay for a more powerful device will have to be more expensive.

Estimated power calculations

To approximately calculate the power of the air conditioner for an apartment, you can apply the following ratio:

  • one kilowatt of cooling capacity per ten meters of area.

Ceilings not higher than three meters. To calculate the power of a domestic air conditioner, the area of ​​the room should be multiplied by 0.1. So, for the service of 30 square meters. meters need 3 kilowatts of cooling power. To reduce the error, roughly calculate the influx of heat from the walls, windows and ceiling. The initial value obtained will increase another 20 percent.

This is a very rough estimate, which is suitable only for residential premises. Thus, the area on the power of the air conditioner directly affects.

More accurate calculation

More detailed calculations take into account not only the power of the air conditioner and the area of ​​the room, but also the direction of the windows (south-north), the number of appliances, people, the presence of ventilation and even number of storeys (the last floors are perfectly “warmed up” through the roof).

M = M1 + M2 + M3, here

M1 - total heat gain from the ceiling, walls and floor. Calculated by the formula:

M1= room area * ceiling height * ratio (30 - 40) \ 1000.

M2 - total heat gain from people present in the room.

An adult at rest emits 0.1 kW,

With physical activity from 0.13 to 0.2 kW.

M3 - heat gain from household appliances, representing 1/3 of the equipment’s power.

Thus, with an error of up to 15%, the power of the air conditioner and the area of ​​the room are recognized.

Heating

Ventilation

Sewerage